Solution #1:
If Janice has pennies, nickels, dimes, and quarters. Using trial and error, I found the following results:
1 of each coin: 0.01 + 0.05 + 0.10 + 0.25 = 0.41
2 of each coin: 0.02 + 0.10 + 0.20 + 0.50 = 0.82
3 of each coin: 0.03 + 0.15 + 0.30 + 0.75 = 1.23
4 of each coin: 0.04 + 0.20 + 0.40 + 1.00 = 1.64
5 of each coin: 0.05 + 0.25 + 0.50 + 1.25 = 2.05
6 of each coin: 0.06 + 0.30 + 0.60 + 1.50 = 2.46
Based upon these results, Janice has 6 of each coin.
Solution #2:
If we let x = the number of coins, then we can set up the equation
0.01x + 0.05x + 0.10x + 0.25x = 2.46 combine like terms
0.41x = 2.46 divide both sides of the equation by 0.41
x = 6
This confirms that Janice has 6 coins of each denomination including pennies, nickels, dimes and quarters.
