Answer:
The answer is "[tex]40.2^{\circ}[/tex]"
Step-by-step explanation:
Please find the graph file.
Let
[tex]\angle EGF = x\\\\\sin x = \frac{12}{18.6}\\\\\sin x = 0.6452 \\\\x = \sin^{-1} (0.64516129) \\\\x = 40.1777695^{\circ} \approx 40.2^{\circ}[/tex]
