Answer:
The ratio of the new volume to the old volume is 8 to 1.
Explanation:
Let's first list what we know:
Since the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.
The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.
Now, let's solve for the volume of the new cube:
[tex]V = s^3[/tex]
[tex]V = 8^3[/tex]
[tex]V = 512[/tex]
The volume of the new cube is 512 [tex]m^3[/tex].
The ratio of the new volume to the old volume is 512 : 64.
Let's simplify the ratio:
512 : 64
8 : 1
The ratio of the new volume to the old volume is 8 to 1.
P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)