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(50 pts will mark brainliest) The perimeter of a rectangle is 48 inches. The width of the rectangle is 4 inches more than 3 times the length of the rectangle. What are the dimensions of the rectangle?

Respuesta :

Answer:

The rectangle is 5 inches long by 19 inches wide.

Step-by-step explanation:

Let's start by listing what we know:

  • The perimeter of a rectangle is 48 inches.
  • The width of the rectangle is 4 inches more than 3 times the length of the rectangle.

Let's represent the width with "w" and length with "l", and make a system of equations based on what we know.

[tex]\left \{ {{2w + 2l = 48} \atop {w = 3l + 4}} \right.[/tex]

Now, let's solve the system of equations using substitution:

[tex]2w + 2l = 48[/tex]

[tex]2 (3l + 4) + 2l = 48[/tex]

[tex]6l + 8 + 2l = 48[/tex]

[tex]8l + 8 = 48[/tex]

[tex]8l = 40[/tex]

[tex]l = 5[/tex]

The length of the rectangle is 5 inches.

Now, let's use this to solve for the width.

[tex]w = 3l + 4[/tex]

[tex]w = 3(5) + 4[/tex]

[tex]w = 15 + 4[/tex]

[tex]w = 19[/tex]

The width of the rectangle is 19 inches.

Let's check our work:

[tex]2w + 2l = 48[/tex]

[tex]2(19) + 2(5) = 48[/tex]

[tex]38 + 10 = 48[/tex]

[tex]48 = 48[/tex]

The results match, so our answer is correct.

The rectangle is 5 inches long by 19 inches wide.