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Type the correct answer in each box. Round your answers to the nearest dollar.


These are the cost and revenue functions for a line of 24-pound bags of dog food sold by a large distributor:






R(x) = -31.72x2 + 2,030x

C(x) = -126.96x + 26,391


The maximum profit of $ Blank

can be made when the selling price of the dog food is set to $ Blank

per bag.

there are two answers

Respuesta :

abidemiokin

Answer:

$10,277.32

Step-by-step explanation:

Given the revenue and cost function

R(x) = -31.72x^2 + 2,030x

C(x) = -126.96x + 26,391

The profit function is expressed as;

P(x) = R(x) - C(x)

P(x) = -31.72x^2 + 2,030x-(-126.96x + 26,391)

P(x) = -31.72x^2 + 2,030x+126.96x - 26,391

P(x) = -31.72x^2 + 2,030x+126.96x - 26,391

P(x) = -31.72x^2 + 2,156.96x - 26,391

To have maximum profit, d

The maximum profit dP/dx = 0

dP/dx = -63.44x+2156.96

-63.44x+2156.96=0

63.44x = 2156.96

X = 2156.96/63.44

x = 34

Get the profit

P(34) = -31.72(34)² + 2,156.96(34)- 26,391

P(34) = -36668.32+73336.64-26391

P(34) = 10,277.32

Hence the maximum profit that can be made is $10,277.32

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