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2Al(S)+1.5O2(S)→Al2O3(s) H= -1676.0 KJ


2Fe + 1.5O2 (S) →Fe2O3(S)


Then the enthalpy change for the following equation is _______KJ


2Al + Fe2 O3(S) → 2Fe +Al2O3(s)
pls i dont have time

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Answer:

[tex]∆H = - 1676.0 - 0 \\ = - 1676.0 \\ heat \: gained \: in \: reaction \: of \: iron \: and \: oxygen \: is \: zero \: because \: it \: is \: not \: given[/tex]

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