Respuesta :

bartdrinksmalk
[tex]\frac{y}{y^{2}-1},\ \frac{y}{y^{2}-8y+7}[/tex]
[tex]=\frac{y}{(y-1)(y+1)},\ \frac{y}{(y-1)(y-7)}[/tex]
[tex]=\frac{y(y-7)}{(y-1)(y+1)(y-7)},\ \frac{y(y+1)}{(y-1)(y+1)(y-7)}[/tex]

So the common denominator is [tex](y-1)(y+1)(y-7)[/tex]

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