Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

a. f(n + 1) = f(n) + 99.4, n ≥ 1
b. f(n + 1) = f(n) – 99.4, n ≥ 1
c. f(n + 1) = 99.4f(n), n ≥ 1
d. f(n + 1) = –99.4f(n), n ≥ 1

Respuesta :

The correct answer is f(n+1)=f(n)-99.4, n≥1
I just completed the problem and it gave me the correct answer so I know this is right.

Answer:

B) f(n+1)=f(n)-99.4 n ≥ 1

Step-by-step explanation: