1) Such area is the area under the curve y = √(x+1) from x=-1 to x=3
2) Such area is the inegral fo the function y = √(x+1) from x= -1 to x=3
3) ∫(√(x+1) = [2/3] (x + 1) ^ (3/2) | from x = -1 to x = 3
[2/3] { (3+1)^(3/2) - (-1 + 1)^(3/2) = [2/3] { √(64) - 0) } = 16/3 = 16/3
Answer: 16/3
