Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?

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26-11-2016
Chemistry

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Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?

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scme1702 scme1702 · Answer 1 · 2016-11-29T18:07:51+01:00

scme1702 scme1702

29-11-2016

We first calculate the decay constant, λ
λ = ln(2) / half life
λ = ln(2) / 14.3

The decay equation is:
N = N(initial) x exp(-λt)
N = 4 x exp(-ln(2)/14.3 x 71.5)
N = 0.125 mg will remain

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