Reaction equation:
Zn + 2HCl → ZnCl₂ + H₂
One mole of gas occupies 22.4 L at STP
Moles of H₂ = 112/22.4
= 5 moles
The theoretical amount of Zn needed is 5 mol
The actual amount = 5/0.85
= 5.88 moles
mass = moles x Mr
mass = 5.88 x 65
mass = 382.2 g
The answer is D.