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Find the area of triangle ABC with the given parts. Round to the nearest whole number.

A = 26.4°
b = 12.3 in.
c = 7.7 in.

a- 19.1 in.2
b- 42.4 in.2
c- 44.4 in.2
d- 21.1 in.2

Respuesta :

[tex]\sin{26.4^o}= \frac{h}{12.3} \\ \\h=12.3\times \sin{26.4^o}=5.47 \\ \\A= \frac{7.7\times5.47}{2}= 21.06[/tex]
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