Answer: [tex]49.7^{\circ}F[/tex]
Step-by-step explanation:
Given
The temperature on the ground is [tex]56.9^{\circ}F[/tex]
temperature drop observed is [tex]1.2^{\circ}F\ \text{per 1000 ft}[/tex]
The height of the plane is [tex]6000\ ft[/tex]
The total increase in height per [tex]1000\ ft[/tex] is [tex]6[/tex] units
Temperature drop is
[tex]\Rightarrow 1.2\times 6=7.2^{\circ}F[/tex]
The temperature at that altitude is
[tex]\Rightarrow 56.9-7.2=49.7^{\circ}F[/tex]
