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A mix of factoring by grouping. Factor the exressions. 17ax+17a-x-1 Please explain/show steps on how to do this!
*edit: I know the answer to the problem because it was said aloud in a class, but I am not sure the steps to get there!

Respuesta :

lublana

Answer:

[tex](x+1)(17a-1)[/tex]

Step-by-step explanation:

We are given that

[tex]17ax+17a-x-1[/tex]

We have to factorize the given expression.

Pair up the terms

[tex](17ax+17a)+(-x-1)[/tex]

Now, taking common factor

[tex]17a(x+1)-1(x+1)[/tex]

Taking common (x+1)

[tex](x+1)(17a-1)[/tex]

Now, we get

[tex](x+1)(17a-1)[/tex]

This is required factors of given expression.