Respuesta :
a) T=2*pi(L/g)^1/2
T=2*3.14(2.5/9.81)^1/2
T=3.171s
b) T=1/f
f=1/3.171
f=0.315Hz
T=2*3.14(2.5/9.81)^1/2
T=3.171s
b) T=1/f
f=1/3.171
f=0.315Hz
a. The period of the child's motion is 3.171 seconds.
b. The frequency of the vibration is 0.315 Hz.
Calculation of the period & frequency:
Since A child swings with a small amplitude on a playground with a 2.5m long chain.
a. So here the time period should be
[tex]2\times \ pi(L/g)^{1/2}\\\\2\times 3.14(2.5/9.81)^{1/2}[/tex]
T=3.171s
b) Now the frequency is
[tex]T=1\div f\\\\f=1\div 3.171[/tex]
f=0.315Hz
learn more about frequency here: https://brainly.com/question/22971850
