Answer:
As viewed on the deck, the lighthouse is 50-6 = 44 m above. First we need to compute the two distances from the captain and the lighthouse. For point1:
d1 = 44 / tan(60) = 25.403 m
For point2:
d2 = 44 / tan(30) = 76.210 m
The distance traveled by the ship in five minutes is 50.807 m or 0.050807 km. Five minutes is equivalent to 1/12 hours.
The speed is then equal to 0.050807/(1/12) kph = 0.61 kph.
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