Answer:
Step-by-step explanation:
A is midpoint of DB
DA ≅ AB ------------------(I)
B is midpoint of AE
BE≅ AB ---------------(II)
From (I) & (II)
DA ≅ AB
∠D ≅ ∠E Given
CD ≅ CE {Sides opposite to equal angles are equal}
ΔCDA ≅ ΔCEB { S A S congruent}
