The expressions that is equivalent to log (12/5) would be A. log (12) - log (5).
When you raise a number with an exponent, there comes a result.
Lets say you get
a^b = c
Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows
b = \log_a(c)
'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'
We have given an expression as ;
log (12/5)
We know that
[tex]log_a(b) - \log_a(c) = \log_a(\frac{b}{c})[/tex]
So,
log (12/5) = log (12) - log (5)
Thus, the correct option is A. log (12) - log (5)
The expressions that is equivalent to log (12/5) would be A. log (12) - log (5).
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