Answer:
d = 4.44 m
Explanation:
Given that,
The moment of force on a door = 10 N-m
The applied force, F = 2.25 N
We need to find the distance of the handle. The moment of force is given by :
[tex]\tau=F\times r[/tex]
Where
r is the distance of the handle.
[tex]r=\dfrac{\tau}{F}\\\\r=\dfrac{10}{2.25}\\\\r=4.44\ m[/tex]
So, the required distance is equal to 4.44 m.
