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Using the fact that at 0.10 M, the absorbance was 0.357; and at 0.20 M, the absorbance was 0.714, the absorptivity (slope) is

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(answer to 2 dec places). Using your absorptivity, if an absorption of 0.250 is measured, the concentration is

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M (answer to 2 dec places)

Respuesta :

Answer:

The answer is "3.57 and 0.07".

Explanation:

Using the slop formula:

[tex]=\frac{n_2-n_1}{n_2-n_1}\\\\ =\frac{0.714-0.357}{0.20-0.10} \\\\ = ABSORPTIVITY, \ \ a=3.57 \\\\A= a\times b \times c[/tex]

Given:

[tex]A=0.250[/tex]

length path [tex]b=1[/tex]  

from calibration it is found that

[tex]a=3.57\\\\consentation \ c=\frac{A}{a\times b} \\\\C=\frac{0.250}{3.57\times 1}[/tex]

   [tex]=0.07 \ M[/tex]

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