Answer:
Ns/Np = 0.171
Explanation:
First, we will find the ratio of lengths of each wire:
[tex]R_{p} = \frac{\rho L_{p}}{A}\\\\R_{s} = \frac{\rho L_{s}}{A}\\[/tex]
where,
Rs = Resistance of secondary coil
Rp = Resistance of Primary Coil
ρ = resistivity of copper
Ls = Length of the secondary coil
Lp = Length of theprimary coil
A = Area of cross-section of wie
Since the material and wire are the same. Therefore, dividing both equations, we get:
[tex]\frac{R_{s}}{R_{p}} = \frac{L_{s}}{L_{p}} \\\\\frac{L_{s}}{L_{p}} = \frac{13}{76}\\\\\frac{L_{s}}{L_{p}} = 0.171\\[/tex]
The number of turns are given as:
[tex]N_{s} = \pi DL_{s}\\N_{p} = \pi DL_{p}\\[/tex]
where,
Ns = No. of turns in the secondary coil
Np = No. of turns in the primary coil
D = Diameter of circular turns
D is the same for both coils. Therefore, dividing both equaions:
[tex]\frac{N_{s}}{N_{p}} = \frac{L_{s}}{L_{p}}\\\\[/tex]
Ns/Np = 0.171
