Answer:
a) 26.66 volts , 266.2 mA
b) 0.458
c) 81%
Explanation:
load ( R ) = 100 Ω
voltage source = 24 volts DC
a) Calculate the rms voltage and current
Vrms = Vp / √ 2
where : Vp = (voltage source * [tex]\pi[/tex]) / 2 = ( 24 *
∴ Vrms = 12[tex]\pi[/tex] / √2 = 26.66 volts
Irms = Vrms / R = 26.66 / 100 = 0.2666 = 266.6 mA
b) Calculate the Ripple factor
Ripple factor for a bridge rectifier = √( 1.1^2 - 1 ) = 0.458
c) Calculate the efficiency of the rectifier
efficiency = ( output dc power ) / Input ac power
= ( 24 / 100 )^2 * 100) / ( 26.66 * 0.2666 )
= 0.0576 * 100 / 7.11 = 0.81 = 81%
