Answer:vocab = ["Libraries", "Bandwidth", "Hierarchy", "Software", "Firewall", "Cybersecurity","Phishing", "Logic", "Productivity"]
print (vocab)
for i in range (1, len (vocab)):
count = i - 1
key = vocab[i]
while (vocab[count] > key) and (count >= 0):
vocab[count+1] = vocab[count]
count -= 1
vocab [count+1] = key
print(vocab)
Explanation: bam baby
In this exercise we have to use the knowledge of the python language to write the code, so we have to:
The code is in the attached photo.
So to make it easier the code can be found at:
vocab = ["Libraries", "Bandwidth", "Hierarchy", "Software", "Firewall", "Cybersecurity","Phishing", "Logic", "Productivity"]
print (vocab)
for i in range (1, len (vocab)):
count = i - 1
key = vocab[i]
while (vocab[count] > key) and (count >= 0):
vocab[count+1] = vocab[count]
count -= 1
vocab [count+1] = key
print(vocab)
See more about python at brainly.com/question/26104476
