2. How will the equilibrium shift if the following changes are made? State if the reaction will shift
to the left or right and explain why it will shift in that direction.
PCl5 () + heat ⇌ PCl3 () + Cl2 ()

a. Temperature is increased
b. pressure is increased
Cl2 is added
d. PCl3 is removed as it is formed
3. How will the equilibrium shift if the following changes are made? State if the reaction will shift
to the left or right and explain why it will shift in that direction. (10 points each. 5 points for
correct answer, 5 points for correct explanation)
H2 () + Cl2 () ⇌ 2HCl() + heat
a. Heat is removed
b.Cl2 is added
d. PCl3 is removed as it is formed
3. How will the equilibrium shift if the following changes are made? State if the reaction will shift
to the left or right and explain why it will shift in that direction.
H2 () + Cl2 () ⇌ 2HCl() + heat
a. Heat is removed
b.HCl is added
c. H2 is added
d. Pressure is decreased
Use the reaction below to answer the following questions.
2NO2 ()⇌N2O4 ()
a. What is the expression for the equilibrium constant, Keq, for the reaction?
b. If there are 0.400 moles of N2O4 and 0.500 moles of NO2 in a 1.00 L flask at equilibrium at 20°C, what is the Keq?

2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.

2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.

2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.

2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.

3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.

3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.

3c. It would shift to the right in order to get rid of the excess form products from it.

3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.

4a. K=[N2O4(g0] / [NO2(g)]2

4b. (Below)

K=[N2O4(g)] / [NO2(g)]2

0.4 / 0.5(2)

0.4/0.25 = 1.6

Keq= 1.6