santoshlama santoshlama

28-03-2021
Mathematics

contestada

sin 2A + sin 5A-sin A÷
cos A + cos 2A + cos 5A

Respuesta :

jamalra0101 jamalra0101

28-03-2021

Answer:

Step-by-step explanation:

(sin5a-sina)+sin2a/(cos5a+cosa)+cos2a

=2cos3asin2a+sin2a/2cos3acos2a+cos2a

=sin2a(2cos3a+1)/cos2a(2cos3a+1)

=sin2a/cos2a

=tan2a

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