Answer:
"Its larger radius"
Explanation:
The electric potential is given by :
[tex]V=\dfrac{kQ}{r}[/tex]
Where
k is the electrostatic constant
Q is electric charge
r is the radius
For Earth, the value of r is very large and Q is very smaller. Due to large r, the potential of Earth's surface is almost zero. Hence, the correct option is (a).
