Given:
The quadratic equation is
[tex]y=6x^2-9x+22[/tex]
To find:
The correct application of the quadratic formula.
Solution:
If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then the quadratic formula is
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
We have,
[tex]y=6x^2-9x+22[/tex]
Putting [tex]y=0[/tex], we get
[tex]6x^2-9x+22=0[/tex]
Here, [tex]a=6,b=-9,c=22[/tex]. Using the quadratic formula, we get
[tex]x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}[/tex]
The correct application of the quadratic formula is [tex]x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}[/tex].
Note: The options are not in proper format.