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If it takes 75.0 mL of 1.5 M HNO3 solution to completely neutralize 125 mL of Ca(OH)2, what is the concentration of the Ca(OH)2 solution?

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Answer:

0.45 M

Explanation:

The reaction that takes place is:

  • 2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O

First we calculate how many HNO₃ moles reacted, using the given concentration and volume:

  • 75.0 mL * 1.5 M = 112.5 mmol HNO₃

Then we convert HNO₃ moles into Ca(OH)₂ moles, using the stoichiometric coefficients:

  • 112.5 mmol HNO₃ * [tex]\frac{1mmolCa(OH)_2}{2mmolHNO_3}[/tex] = 56.25 mmol Ca(OH)₂

Finally we calculate the concentration of the Ca(OH)₂ solution:

  • 56.25 mmol Ca(OH)₂ / 125 mL = 0.45 M

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