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I WILL GIVE BRAINLIEST Given: BFCE, AB perpendicular to BE, DE perpendicular to BE,

angle BFD equal to angle ECA

Prove triangle ABC is similar to triangle DEF

I WILL GIVE BRAINLIEST Given BFCE AB perpendicular to BE DE perpendicular to BEangle BFD equal to angle ECAProve triangle ABC is similar to triangle DEF class=

Respuesta :

Answer:

Step-by-step explanation:

From the given picture,

∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]

m∠ECA = m∠BFD [Given]

m∠ECA + m∠ACB = 180° [Liner pair of angles]

m∠BFD + m∠DFE = 180° [Liner pair of angles]

m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]

m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]

Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]

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