Answer:
[tex](x-6)^{2} + (y+3)^{2} =41[/tex]
Step-by-step explanation:
Equation of circle is
[tex](x-a)^{2} + (y-b)^{2} =r^{2}[/tex]
Where (a, b) is center of circle and r is radius
Here (a, b) = (6, -3) and radius can be determined by calculating the distance from center to point (1, 1)
[tex]r=\sqrt{(6-1)^2 +(-3-1)^2} \\r= \sqrt{25+16}\\r= \sqrt{41}[/tex]
Substituting values in equation of circle
[tex](x-6)^{2} + (y+3)^{2} =41[/tex]
