Question:-
solve it:-[tex]\sf{\dfrac{3x-5}{3}=11x-5 }[/tex]
Answer:
[tex]\dashrightarrow\bold{\dfrac{3x-5}{3}=11x-5 }[/tex]
[tex]\dashrightarrow\bold{3 \times (11x-5)=3x-5 }[/tex]
[tex]\dashrightarrow\bold{(3 \times 11x)-(3\times 5)=3x-5 }[/tex]
[tex]\dashrightarrow\bold{33x-15=3x-5 }[/tex]
[tex]\longrightarrow \bold{33x-3x=-5+15 }[/tex]
[tex]\longrightarrow \bold{30x=10 }[/tex]
[tex]\mapsto\bold{x=\dfrac{10}{30} }[/tex]
[tex]\mapsto\bold{x=\dfrac{1\cancel{0}}{3\cancel{0}} }[/tex]
[tex]\hookrightarrow\tt{x=\dfrac{1}{3} }[/tex]
