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An object moves along a circular track of radius 3.00 m. The object completes one loop around the track in 4.00 s. Determine the centripetal acceleration of the object.

Respuesta :

Answer:

a = 7.4 m / s²

Explanation:

The centripetal acceleration of an object that has constant speed is

         a = v² / r

linear and angular velocity are related

         v = w r

let's substitute

         a = w² r

the angular velocity is related to the period

        w = 2π / T

we substitute

        a = [tex]\frac{4\pi ^2 \ r}{T^2}[/tex]

let's calculate

        a = 4π²  3.00 /4²

        a = 7.4 m / s²

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