Answer: Jane's height = [tex]51\dfrac{1}{20}\text{ inches}[/tex]
Step-by-step explanation:
Given: Lisa's height = [tex]53\dfrac34\text{ inches}=\dfrac{4\times53+3}{4}\text{ inches}[/tex]
[tex]=\dfrac{215}{4}\text{ inches}[/tex]
Joey's height = [tex]\dfrac{215}4-1\dfrac12[/tex] inches
[tex]=\dfrac{215}4-\dfrac32\\\\=\dfrac{215-6}{4}\\\\=\dfrac{209}{4}\text{ inches}[/tex]
Jane's height = [tex]\dfrac{209}{4}-1\dfrac15[/tex] inches
[tex]=\dfrac{209}{4}-\dfrac{6}{5}\\\\=\dfrac{209\times5-6\times4}{20}\\\\=\dfrac{1045-24}{20}\\\\=\dfrac{1021}{20}\\\\=51\dfrac{1}{20}\text{ inches}[/tex]
Hence, Jane's height = [tex]51\dfrac{1}{20}\text{ inches}[/tex]
