If each of these runners travels the indicated number of spaces in the same amount of time, at which numbered spot will all of the runners be next to one another?

If each of these runners travels the indicated number of spaces in the same amount of time at which numbered spot will all of the runners be next to one another class=

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Answer:

nub 5

Step-by-step explanation:

The Least Common Multiple, LCM, also known as the Lowest Common Multiple or  Least Common Divisor, LCD, of two numbers is the smallest natural number that can be divided evenly by either of the two numbers

  • The numbered spot at which all the runners will be next to one another is spot 19

Reason:

The given parameters, starting from the runner on the outer track are;

Number of spaces covered by the runner on the outer track, n₁ = 5 spaces

Number of spaces covered by the next inner runner, n₂ = 1 space

Number of spaces covered by the next inner runner, n₃ = 3 spaces

Number of spaces covered by the next runner, n₄ = 2 spaces

The numbered spot at which all the runners will be next to one another = Required

Solution:

A spot where all the runners will be next to one another is given by the Lowest Common Multiple, LCM, of their speeds or number of spaces traveled in the same time as follows;

The LCM of 5, 1, 3, and 2 = 5 × 1 × 3 × 2 = 30

Therefore, when the first runner runs 30 spaces, we have;

[tex]Time = \dfrac{30}{5} = 6[/tex]

The time taken is 6 time units

The point the runner stops is at space 30- (30 -19) = Spot 19

  • New location of the first runner = Spot 19

The distance traveled by the runner 2 at the same time is 6 × 1 = 6

∴ The distance traveled by the runner 2 at the same time = 6 spaces

  • New location of the second runner = 6 Spaces + Spot 13 = Spot 19

The distance traveled by the runner 3 at the same time is 6 × 3 = 18

∴ The distance runner 3 travels at the same time = 18 spaces

  • New location of the third runner = 18 Spaces + Spot 1 = Spot 19

Runner 4 travels a distance at the same time of  6 × 2 = 12

∴ Distance runner 4 travels = 12 spaces

  • New location of runner 4 = 12 spaces + Spot 7 = Spot 19

Therefore;

The numbered spot at which all the runners will be next to one another is spot 19

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