First you simplyify both sides,
8x+6<5x+21
Then you subtract both sides,
8x+(6−5x)<5x+(21−5x)
3x+6<21
Subtract 6 from both sides,
3x+6−6<21−6
3x<15
finally you divide both sides by 3,
[tex] \frac{3x}{3} \ \textless \ \frac{15}{3} [/tex]
Your answer is:x<5
Glad I could help. c:
