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A 0.140-kg baseball is pitched horizontally at 33.6 m/s. When a player hits the ball, it moves at the
same speed, but in the opposite direction. If the bat and the ball are in contact for 0.008 s, calculate the
average force the bat exerts on the ball.

Respuesta :

Answer:

F = 1176 N

Explanation:

Given that,

Mass of a baseball, m = 0.140-kg

Initial speed of the baseball, u = 33.6 m/s

Final speed of the baseball, v = -33.6 m/s (in opposite direction)

The time of contact of the bat and the ball, t = 0.008 s

We need to find the  average force the bat exerts on the ball. The force acting on the ball is given by :

[tex]F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.14(-33.6-33.6)}{0.008}\\F= -1176\ N[/tex]

So, the average force the bat exerts on the ball is 1176 N.

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