Answer:
530.43m/s
Explanation:
Given data
Mass m = 0.23kg
PE= 61J
From the expression for potential energy
PE= mgh
after it was shot
PE=KE
KE= 1/2mv^2
So
PE= 1/2mv^2
substitute
61= 1/2*0.23*v^2
61=0.5*0.23*v^2
61=0.115v^2
divide both sides by 0.115
v= 61/0.115
v=530.43 m/s
Hence the velocity is 530.43m/s
