kcool2005 kcool2005

29-01-2021
Mathematics

contestada

Factor completely. x4+4x3−27x−108

Respuesta :

surjithayer10 surjithayer10

29-01-2021

Answer:

Step-by-step explanation:

[tex]x^4+4x^3-27x-108\\=x^3(x+4)-27(x+4)\\=(x+4)(x^3-27)\\=(x+4)[x^3-3^3]\\=(x+4)(x-3)(x^2+3x+3)[/tex]

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