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A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 193.0 km/h. The conditions at the airport are ideal, there is no wind. When the engine is running at its full power, the acceleration of the airplane is 2.80 m/s2. What is the minimum required length of the runway

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Answer:

513 m

Explanation:

We have;

final speed of the airplane = 193.0 km/h * 1000/3600 = 53.6 m/s

acceleration of the air plane = 2.80 m/s2

initial velocity of the airplane = 0 m/s

length of the runway = distance covered

v^2 = u^2 + 2as

v^2 - u^2 = 2as

s = v^2 - u^2/2a

s = (53.6)^2 - 0^2/ 2 *  2.80

s = 2872.96/ 5.6

s = 513 m

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