Answer:
g = 3.125 m/s²
Explanation:
To find the acceleration due to gravity we will use the second equation of motion:
[tex]h = V_{i}t + \frac{1}{2}gt^{2}\\[/tex]
where,
h = height = 1 m
Vi = initial speed object = 0 m/s (object is initially at rest)
t = time taken = 0.8 s
g = acceleration due to gravity = ?
Therefore,
[tex]1\ m = (0\ m/s)(0.8\ s)+\frac{1}{2}g(0.8\ s)^{2}\\\\\frac{2\ m}{0.64\ s^{2}} = g\\\\[/tex]
g = 3.125 m/s²
