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A2.0kg arrow is fired at 10m/s into a stationary 10 kg block of ice as shown below: the arrow sticks into the block of ice and they start moving . What is the velocity of the arrow/ice combination after the collison

Respuesta :

Answer:

the velocity is 1.67 m/s

Explanation:

The computation of the velocity of the arrow/ice combination after the collison is shown below:

Here the law of conservation is applied

[tex]p_i = p_f\\\\m_av_a+m_b+v_b= (m_a + m_b)v[/tex]

Here

[tex]m_a = 2.0 kg\\\\v_a = 10m/s\\\\m_b = 10 kg\\\\v_b = 0[/tex]

Now

[tex]v = \frac{m_av_a+ m_bv_b}{m_a + m_b} \\\\= \frac{(2.0kg) (10 m/s) + 0}{2.0kg + 10.0kg}[/tex]

= 1.67 m/s

hence, the velocity is 1.67 m/s

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