Assuming we are solving for the variable x...
You want to flip the equation so > [tex] \frac{2}{3}x - 1 = y [/tex]
Then you want to add 1 to both sides.
[tex] \frac{2}{3}x - 1 + 1 = y + 1 \ \textgreater \ \frac{2}{3}x = y + 1 [/tex]
Then we want to divide both sides by [tex] \frac{2}{3} [/tex]
[tex] \frac{2}{3}x/ \frac{2}{3} = \frac{y + 1}{ \frac{2}{3} } \ \textgreater \ x = \frac{3y + 3}{2} [/tex]
So our final answer is [tex] \frac{3y + 3}{2} [/tex]
