Tran has a coin jar that contains​ nickels, dimes, and quarters. There are 185 coins in the jar. There are 5 more dimes than quarters. If the total value of the coins in the jar is $25.25 how many quarters does the jar​ contain?

Respuesta :

Answer:

[tex]63[/tex]

Step-by-step explanation:

Let number of nickels be [tex]x[/tex]

Number of dimes be [tex]y[/tex]

Number of quarters be [tex]z[/tex]

Total number of coins is [tex]185[/tex]

[tex]x+y+z=185[/tex]

Number of dimes is 5 more than quarters

[tex]y=5+z[/tex]

[tex]x+(5+z)+z=185\\\Rightarrow x+2z=180\\\Rightarrow x=180-2z[/tex]

Amount of money in the jar is $25.25

[tex]0.05x+0.1y+0.25z=25.25\\\Rightarrow 0.05x+0.1(5+z)+0.25z=25.25\\\Rightarrow 0.05x+0.5+0.1z+0.25z=25.25\\\Rightarrow 0.05x+0.35z=24.75[/tex]

[tex]0.05(180-2z)+0.35z=24.75\\\Rightarrow 9-0.1z+0.35z=24.75\\\Rightarrow 9+0.25z=24.75\\\Rightarrow z=\dfrac{24.75-9}{0.25}\\\Rightarrow z=63[/tex]

[tex]y=5+z=5+63\\\Rightarrow y=68[/tex]

[tex]x=180-2z=180-2\times 63\\\Rightarrow x=54[/tex]

So, the number of quarters is [tex]63[/tex].

Answer:

63 is the correct answer :)

Step-by-step explanation: