Answer:
[tex]d = 10[/tex]
Step-by-step explanation:
Distance formula
[tex]d =\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }[/tex] ------------ (1)
Here
[tex](x_1, y_1) = (6, 2) \ \ \ and \ \ \ (x_2, y_2) = (5, 9)[/tex]
Substituting values in equation (1)
[tex]d =\sqrt{(5-6)^{2} + (9-2)^{2} }[/tex]
[tex]d =\sqrt{(-1)^{2} + (7)^{2} }[/tex]
[tex]d = \sqrt { 50 }[/tex]
[tex]d=7.07[/tex]
the nearest tenth is 10
