contestada

Which of the following is an improper integral?
A) the integral from 0 to 3 of the quotient of the quantity x plus 1 and the quantity 3 times x minus 2 dx
B) the integral from 1 to 3 of the quotient of the quantity x plus 1 and the quantity 3 times x minus 2 dx
C) the integral from negative 1 to 0 of the quotient of the quantity x plus 1 and the quantity 3 times x minus 2 dx
D) None of these

Respuesta :

Space

Answer:

A)  [tex]\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx[/tex]

General Formulas and Concepts:

Calculus

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C
  • Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A)  [tex]\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx[/tex]

B)  [tex]\displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx[/tex]

C)  [tex]\displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx[/tex]

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

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