Respuesta :

Answer:

New temperature T2 = 16.59°C Approx

Explanation:

Given:

Old volume V1 = 2.36 L

Old temperature T1 = 27°C

New volume V2 = 1.45 L

Find:

New temperature T2

Computation:

Using Charles's Law;

V1T2 = V2T1

(2.36)(T2) = (1.45)(27)

New temperature T2 = 16.59°C Approx