carminahershey
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PLEASE HELP ITS AN ENERGENCY Which equation of a line is parallel to the graph of y = 3x - 5 and passes through the point (1,5)?

A.) y = 3x + 2
B.) y = 3x - 14
C.) y = 1/3x+8/3
D.) y = -1/3x+16/3

Respuesta :

tataplayer10

Since it's paralel, it's angular coeficient must be the same.

[tex]f(x) =ax+b[/tex]

[tex]f(x) = 3x+b[/tex]

We know that the function passes through the point (1,5), then:

[tex]f(1) = 5[/tex]

[tex]3+b = 5[/tex]

[tex]b = 2[/tex]

The function is:

[tex]f(x) = 3x+2[/tex]

A.) y = 3x + 2

Cricetus

The equation of the line will be "y = 3x + 2".

Given:

  • [tex]y =3x-5[/tex]

or,

  • [tex]3x-y-5=0[/tex]

Point,

  • (1, 5) = (x, y)

The equation of the line which parallel to the given equation will be:

  • [tex]3x-y+C=0[/tex]

By substituting the value of "x" and "y" in the above expression, we get

→ [tex](3\times 1)-5+C=0[/tex]

→          [tex]3-5+C=0[/tex]

→              [tex]-2+C=0[/tex]

→                       [tex]C = 2[/tex]  

Therefore the equation of line is "[tex]3x-y+2=0[/tex]". Thus the above answer i.e., option A is correct.

Learn more about equation of line here:

https://brainly.com/question/23346308

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