Answer:
Point-slope equation for the line is
[tex]y-2= -\frac {3}{2} (x -0)[/tex]
Step-by-step explanation:
Equation of straight line in slope intercept form is given as
[tex]y-y_1=m(x-x_1)[/tex] ---------- (1)
Here
Slope [tex]m=-\frac{3}{2}[/tex]
Any Passing Point [tex](x_1, y_1) = (0, 2)[/tex]
Substituting values in equation (1)
[tex]y-2= -\frac {3}{2} (x -0)[/tex]
