Answer:
see explanation
Step-by-step explanation:
note that [tex]\sqrt{-1}[/tex] = i
[tex]\sqrt{64-112}[/tex]
= [tex]\sqrt{-48}[/tex]
= [tex]\sqrt{16(3)(-1)}[/tex]
= [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex] × [tex]\sqrt{-1}[/tex]
= 4 × [tex]\sqrt{3}[/tex] × i
= 4i[tex]\sqrt{3}[/tex]
