Assuming you mean 2y² + 3y = 2 we are solving the quadratic
To solve a quadratic formula you need to know the formula.
Formula > x1, 2 = [tex]\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Now we must plug in the values. a = 2 b = 3 c = -2
[tex]y=\frac{-3+\sqrt{3^2-4\cdot \:2\left(-2\right)}}{2\cdot \:2}=\frac{1}{2} \ \textgreater \ y=\frac{-3-\sqrt{3^2-4\cdot \:2\left(-2\right)}}{2\cdot \:2}=-2 [/tex]
So now we know our answer should be {1/2, -2}
